(3y+5)(2y^2+5y-6)=0

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Solution for (3y+5)(2y^2+5y-6)=0 equation: 


Simplifying
(3y + 5)(2y2 + 5y + -6) = 0

Reorder the terms:
(5 + 3y)(2y2 + 5y + -6) = 0

Reorder the terms:
(5 + 3y)(-6 + 5y + 2y2) = 0

Multiply (5 + 3y) * (-6 + 5y + 2y2)
(5(-6 + 5y + 2y2) + 3y * (-6 + 5y + 2y2)) = 0
((-6 * 5 + 5y * 5 + 2y2 * 5) + 3y * (-6 + 5y + 2y2)) = 0
((-30 + 25y + 10y2) + 3y * (-6 + 5y + 2y2)) = 0
(-30 + 25y + 10y2 + (-6 * 3y + 5y * 3y + 2y2 * 3y)) = 0
(-30 + 25y + 10y2 + (-18y + 15y2 + 6y3)) = 0

Reorder the terms:
(-30 + 25y + -18y + 10y2 + 15y2 + 6y3) = 0

Combine like terms: 25y + -18y = 7y
(-30 + 7y + 10y2 + 15y2 + 6y3) = 0

Combine like terms: 10y2 + 15y2 = 25y2
(-30 + 7y + 25y2 + 6y3) = 0

Solving
-30 + 7y + 25y2 + 6y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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